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Make menu update more resistant to HTTP errors and API changes

Toni Fadjukoff 6 years ago
parent
commit
76ee24eaa3
1 changed files with 10 additions and 5 deletions
  1. 10 5
      food.py

+ 10 - 5
food.py View File

@@ -39,11 +39,12 @@ unordered = []
39 39
 l = time.localtime()
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 this_week = datetime.datetime.now().isocalendar()[1]
41 41
 
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-unordered += amica.get_restaurants(use_old, this_week)
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-unordered += juvenes.get_restaurants(use_old, this_week)
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-unordered += sodexo.get_restaurants(use_old, this_week)
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-unordered += campusravita.get_restaurants(use_old, this_week)
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-
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+updateException = None
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+for restaurant_module in [sodexo, amica, juvenes, campusravita]:
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+    try:
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+        unordered += restaurant_module.get_restaurants(use_old, this_week)
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+    except Exception as e:
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+        updateException = e
47 48
 
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 max_week = 0;
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 for r in unordered:
@@ -411,3 +412,7 @@ all_restaurants = get_restaurants_sorted(unordered);
411 412
 
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 write_all_days(all_restaurants, "", all_title, "");
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 write_table(all_restaurants, "", all_title, "");
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+
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+if updateException is not None:
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+    print("Exception happened while fetching menus")
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+    raise updateException